Let $f : X \to Y$ be a D18: Map such that

(i)	$B_j \subseteq Y$ is a D78: Subset of $Y$ for each $j \in J$

Then \begin{equation} f^{-1} \left( \bigcap_{j \in J} B_j \right) = \bigcap_{j \in J} f^{-1}(B_j) \end{equation}