Applying results
we have
\begin{equation}
\begin{split}
\int^a_{-a} f(x) \, d x & = \int^a_0 f(x) \, d x + \int^0_{-a} f(x) \, d x \\
& = \int^a_0 f(x) \, d x + \int^a_0 f(-x) \, d x \\
& = \int^a_0 f(x) \, d x + \int^a_0 f(x) \, d x \\
& = 2 \int^a_0 f(x) \, d x
\end{split}
\end{equation}
$\square$