Let $P = (\Omega, \mathcal{F}, \mathbb{P})$ be a [[[d,1159]]]. If $I_E$ is an [[[d,2796]]] on $P$ for $E \in \mathcal{F}$, then the distribution of $I_E$ is immediately given by $\mathbb{P}(I_E = 1) = \mathbb{P}(E)$ and $\mathbb{P}(I_E = 0) = \mathbb{P}(\Omega \setminus E)$.